Geometry: The AAS Theorem
The AAS Theorem
You've accepted several postulates in this section. That's enough faith for a while. It's time for your first theorem, which will come in handy when trying to establish the congruence of two triangles.
- Theorem 12.2: The AAS Theorem. If two angles and a nonincluded side of one triangle are congruent to two angles and a nonincluded side of a second triangle, then the triangles are congruent.
Figure 12.7 will help you visualize the situation. In the following formal proof, you will relate two angles and a nonincluded side of ?AB to two angles and a nonincluded side of ?RST.
- Given: Two triangles, ?ABC and ?RST, with ?A ~= ?R , ?C ~= ?T , and BC ~= ST.
- Prove: ?ABC ~= ?RST.
- Proof: You need a game plan. If only you knew about two angles and the included side! Then you would be able to use the ASA Postulate to conclude that ?ABC ~= ?RST. But wait a minute! Because the measures of the interiorangles of a triangle add up to 180, and you know two of the angles in are congruent to two of the angles in ?RST, you can show that the third angle of ?ABC is congruent to the third angle in ?RST. Then you'll have two angles and the included side of ?ABC congruent to two angles and the included side of ?RST, and you're home free.
|1.||?ABC and ?RST with ?A ~= ?R , ?C ~= ?T , and BC ~= ST.||Given|
|2.||m?A = m?R and m?C = m?T||Definition of ~=|
|3.||m?A + m?B + m?C = 180 and m?R + m?S + m?T = 180||Theorem 11.1|
|4.||m?A + m?B + m?C = m?R + m?S + m?T||Substitution (step 3)|
|5.||m?A + m?B + m?C = m?A + m?S + m?C||Substitution (steps 2 and 4)|
|6.||m?B = m?S||Algebra|
|7.||?B ~= ?S||Definition of ~=|
|8.||?ABC ~= ?RST||ASA Postulate|
The HL Theorem for Right Triangles
Whenever you are given a right triangle, you have lots of tools to use to pick out important information. For example, not only do you know that one of the angles of the triangle is a right angle, but you know that the other two angles must be acute angles. You also have the Pythagorean Theorem that you can apply at will. Finally, you know that the two legs of the triangle are perpendicular to each other. You've made use of the perpendicularity of the legs in the last two proofs you wrote on your own. Now it's time to make use of the Pythagorean Theorem.
- Theorem 12.3: The HL Theorem for Right Triangles. If the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of a second right triangle, then the triangles are congruent.
There are several ways to prove this problem, but none of them involve using an SSA Theorem. Your plate is so full with initialized theorems that you're out of room. Not to mention the fact that a SSA relationship between two triangles is not enough to guarantee that they are congruent. If you use the Pythagorean Theorem, you can show that the other legs of the right triangles must also be congruent. Then it's just a matter of using the SSS Postulate.
Figure 12.8 illustrates this situation. You have two right triangles, ?ABC and ?RST.
- Given: ?ABC and ?RST are right triangles with AB ~= RS and BC ~= ST.
- Prove: ?ABC ~= ?RST.
- Proof: You already have a game plan, so all that's left is to execute it.
|1.||?ABC and ?RST are right triangles with AB ~= RS and ~= ST.||Given|
|2.||AB = RS and BC = ST||Definition of ~=|
|3.||(AC)2 + (BC)2 and (RT)2 + (ST)2 = (RS)2||The Pythagorean Theorem|
|4.||(AC)2 + (BC)2 = (RT)2 + (ST)2||Substitution (steps 2 and 3)|
|5.||(AC)2 + (ST)2 = (RT)2 + (ST)2||Substitution (steps 2 and 4)|
|6.||(AC)2 = (RT)2||Algebra|
|7.||AC = RT||Algebra|
|8.||AC ~= RT||Definition of ~=|
|9.||?ABC ~= ?RST||SSS Postulate|
SSS, SAS, ASA, and AAS are valid methods of proving triangles congruent, but SSA and AAA are not valid methods and cannot be used. In Figure 12.9, the two triangles are marked to show SSA, yet the two triangles are not congruent. Figure 12.10 shows two triangles marked AAA, but these two triangles are also not congruent.
Excerpted from The Complete Idiot's Guide to Geometry 2004 by Denise Szecsei, Ph.D.. All rights reserved including the right of reproduction in whole or in part in any form. Used by arrangement with Alpha Books, a member of Penguin Group (USA) Inc.
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