1999 Women's World Cup Qualifying CONCACAF
Updated September 27, 2017 |
Infoplease Staff
Two or three teams qualify including the host United States which receives and automatic bid. The tournament runner-up advances to a two-leg playoff against the runner-up from South America.
| Group A | W | L | T | GF | GA | Pts |
|---|---|---|---|---|---|---|
| †Canada | 3 | 0 | 0 | 39 | 0 | 9 |
| †Guatemala | 2 | 1 | 0 | 10 | 4 | 6 |
| Martinique | 1 | 2 | 0 | 9 | 16 | 3 |
| Puerto Rico | 0 | 3 | 0 | 0 | 38 | 0 |
| Group B | W | L | T | GF | GA | Pts |
|---|---|---|---|---|---|---|
| †Mexico | 2 | 0 | 1 | 12 | 4 | 7 |
| †Costa Rica | 2 | 1 | 0 | 6 | 5 | 6 |
| Trinidad & Tobago | 1 | 1 | 1 | 5 | 6 | 4 |
| Haiti | 0 | 3 | 0 | 3 | 12 | 0 |
| Semifinals | |
|---|---|
| Mexico 8 | Guatemala 0 |
| Canada 2 | Costa Rica 0 |
| Finals | |
|---|---|
| *Canada 1 | Mexico 0 |
| Third Place | |
| Costa Rica 4 | Guatemala 0 |
REMAINING GAME: South America runner-up (Argentina) vs. CONCACAF runner up (Mexico) in a two-leg playoff.
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